What is the solution for y^{''}-14y^'+74y=0 ?

The solution for y^{''}-14y^'+74y=0 is y=e^{7t}(c_{1}cos(5t)+c_{2}sin(5t))

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y^{''}-14y^'+74y=0

y^{^{''}} - 14 y^{^{'}} + 74 y = 0

y = e^{7 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

Solution steps

y^{''} (t) - 14 y^{'} (t) + 74 y = 0

Solve linear ODE:

y = e^{7 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

y = e^{7 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

\int_{0}^{\frac{π}{2}} sin^{2} (3 x) d x

\int 5 x ln (2 x) d x

\int \frac{ln ( x ^{15} )}{x} d x

\int \frac{x + 9}{x ^{2} - 6 x + 9} d x

y (\frac{π}{21}) = 2 tan^{2} (7 x)

What is the solution for y^{''}-14y^'+74y=0 ?
The solution for y^{''}-14y^'+74y=0 is y=e^{7t}(c_{1}cos(5t)+c_{2}sin(5t))