What is the sum from n=1 to infinity}4^{n+1 of 5^{-n} ?

The sum from n=1 to infinity}4^{n+1 of 5^{-n} is converges

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sum from n=1 to infinity}4^{n+1 of 5^{-n}

n = 1 \sum \infty 4^{n + 1} 5^{- n}

converges

Solution steps

n = 1 \sum \infty 4^{n + 1} \cdot 5^{- n}

Apply Series Ratio Test:

converges

= converges

\frac{d y}{d x}, y = 8 x

\frac{d}{d x} (- 2 e^{3 x})

\int_{1}^{9} \frac{5}{3 x} d x

y^{^{'}} = \frac{e ^{x - y}}{1 + e ^{x}}

\frac{\partial}{\partial x} (3 x^{2} y + 4 x z^{3})

What is the sum from n=1 to infinity}4^{n+1 of 5^{-n} ?
The sum from n=1 to infinity}4^{n+1 of 5^{-n} is converges