What is the integral of (x^2)/(1-2x^3) ?

The integral of (x^2)/(1-2x^3) is -1/6 ln|1-2x^3|+C

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integral of (x^2)/(1-2x^3)

\int \frac{x ^{2}}{1 - 2 x ^{3}} d x

- \frac{1}{6} ln 1 - 2 x^{3} + C

Solution steps

\int \frac{x ^{2}}{1 - 2 x ^{3}} d x

Apply u-substitution

: \int - \frac{1}{6 u} d u

= \int - \frac{1}{6 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{6} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{6} ln ∣ u ∣

Substitute back

u = 1 - 2 x^{3}

= - \frac{1}{6} ln 1 - 2 x^{3}

Add a constant to the solution

= - \frac{1}{6} ln 1 - 2 x^{3} + C

\frac{d}{d x} (\frac{e ^{x}}{7 x ^{2} + 9})

x \to - 7 lim (12)

x^{2} - 8 x + 17

\int (x^{2} + 5) (x - 3) d x

\frac{x}{x ^{2} + 1}

What is the integral of (x^2)/(1-2x^3) ?
The integral of (x^2)/(1-2x^3) is -1/6 ln|1-2x^3|+C