What is the derivative of (2x^2)+(sqrt(x-8)) ?

The derivative of (2x^2)+(sqrt(x-8)) is 4x+1/(2sqrt(x-8))

What is the first derivative of (2x^2)+(sqrt(x-8)) ?

The first derivative of (2x^2)+(sqrt(x-8)) is 4x+1/(2sqrt(x-8))

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derivative of

(2 x^{2}) + (x - 8)

4 x + \frac{1}{2 x - 8}

Solution steps

\frac{d}{d x} (2 x^{2} + x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (x - 8)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (x - 8) = \frac{1}{2 x - 8}

= 4 x + \frac{1}{2 x - 8}

x \to 5 lim (\frac{x + 5}{x - 5})

x \to 0 lim (\frac{x}{x ^{2} + 4 x})

n = 1 \sum \infty (1 - \frac{3}{n})^{n}

\int (e^{\frac{x}{2}}) d x

\frac{\partial}{\partial x} (2 x yz - y e^{2 x yz})

What is the derivative of (2x^2)+(sqrt(x-8)) ?
The derivative of (2x^2)+(sqrt(x-8)) is 4x+1/(2sqrt(x-8))
What is the first derivative of (2x^2)+(sqrt(x-8)) ?
The first derivative of (2x^2)+(sqrt(x-8)) is 4x+1/(2sqrt(x-8))