What is the tangent of 6/x ?

The tangent of 6/x is y=-6/(a_{0)^2}x+(12)/(a_{0)}

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tangent of 6/x

tangent of

\frac{6}{x}

y = - \frac{6}{a _{0}^{2}} x + \frac{12}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{6}{a _{0}})

Find the slope of

y = \frac{6}{x} : \frac{d y}{d x} = - \frac{6}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{6}{a _{0}^{2}}

Find the line with slope m=

- \frac{6}{a _{0}^{2}}

and passing through

(a_{0}, \frac{6}{a _{0}}) : y = - \frac{6}{a _{0}^{2}} x + \frac{12}{a _{0}}

y = - \frac{6}{a _{0}^{2}} x + \frac{12}{a _{0}}

\int (2 x^{4} - 1) (5 x^{3} + 6 x) d x

f (- 3) = - 2 x^{2} + 4 x - \frac{7}{x ^{2}}

\frac{d y}{d x} = y (x y^{4} - 1)

f (x) = - \frac{4}{x}

n = 0 \sum \infty 5 (\frac{3}{4})^{n}