What is the sum from n=0 to infinity of 5(3/4)^n ?

The sum from n=0 to infinity of 5(3/4)^n is 20

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sum from n=0 to infinity of 5(3/4)^n

n = 0 \sum \infty 5 (\frac{3}{4})^{n}

20

Solution steps

n = 0 \sum \infty 5 (\frac{3}{4})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty (\frac{3}{4})^{n}

Apply Series Geometric Test:

4

= 5 \cdot 4

Simplify

= 20

\int sech^{4} (x) tanh (x) d x

4 x y^{^{'}} + 4 y = 3

x^{5} + 1, x + 1, - 1, 0

5 x - 6 y x^{2} + 1 \frac{d y}{d x} = 0

x \to 2 lim (x^{2} - 3 x + 8)

What is the sum from n=0 to infinity of 5(3/4)^n ?
The sum from n=0 to infinity of 5(3/4)^n is 20