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Popular >

integral from 0 to 2 of 8x-4x^2

Solution

\int_{0}^{2} 8 x - 4 x^{2} d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{0}^{2} 8 x - 4 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 8 x d x - \int_{0}^{2} 4 x^{2} d x

\int_{0}^{2} 8 x d x = 16

\int_{0}^{2} 4 x^{2} d x = \frac{32}{3}

= 16 - \frac{32}{3}

Simplify

16 - \frac{32}{3} : \frac{16}{3}

= \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of 8x-4x^2 ?
The integral from 0 to 2 of 8x-4x^2 is 16/3