What is the limit as x approaches 0-of 4+6/(x^2) ?

The limit as x approaches 0-of 4+6/(x^2) is infinity

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limit as x approaches 0-of 4+6/(x^2)

x \to 0 - lim (4 + \frac{6}{x ^{2}})

\infty

Solution steps

x \to 0 - lim (4 + \frac{6}{x ^{2}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (4) + x \to 0 - lim (\frac{6}{x ^{2}})

x \to 0 - lim (4) = 4

x \to 0 - lim (\frac{6}{x ^{2}}) = \infty

= 4 + \infty

Apply Infinity Property:

c + \infty = \infty

= \infty

f (x) = x^{2}, at x = - 1

\int \frac{1}{z} d z

\frac{d x}{d t} + 5 t x^{3} + \frac{x}{t} = 0

x y y^{^{'}} = x^{2} + 1

\int 4 x ln (x) d x

What is the limit as x approaches 0-of 4+6/(x^2) ?
The limit as x approaches 0-of 4+6/(x^2) is infinity