What is the integral of 1/(sqrt(z)) ?

The integral of 1/(sqrt(z)) is 2sqrt(z)+C

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integral of 1/(sqrt(z))

\int \frac{1}{z} d z

2 z + C

Solution steps

\int \frac{1}{z} d z

Apply the Power Rule

: 2 z^{\frac{1}{2}}

= 2 z^{\frac{1}{2}}

Apply radical rule:

a^{\frac{1}{n}} = n a

= 2 z

Add a constant to the solution

= 2 z + C

\frac{d x}{d t} + 5 t x^{3} + \frac{x}{t} = 0

x y y^{^{'}} = x^{2} + 1

\int 4 x ln (x) d x

x^{2} - x y + y^{2} = 3, (1, 2)

\frac{4 x ^{5} + 5}{x ^{3}}