What is area 7cos(7x),7-7cos(7x),[0, pi/7 ] ?

The answer to area 7cos(7x),7-7cos(7x),[0, pi/7 ] is -(2pi)/3+pi+2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 7cos(7x),7-7cos(7x),[0, pi/7 ]

area

7 cos (7 x), 7 - 7 cos (7 x), [0, \frac{π}{7}]

- \frac{2 π}{3} + π + 23

Decimal

4.51129 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{7}} ∣ 7 cos (7 x) - (7 - 7 cos (7 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{7}} ∣ 7 cos (7 x) - (7 - 7 cos (7 x)) ∣ d x : - \frac{2 π}{3} + π + 23

The area is:

= - \frac{2 π}{3} + π + 23

5 y x^{2} + 1 \frac{d y}{d x} + 4 x = 0

\frac{d}{d x} (\frac{1}{( 3 x + 1 ) ^{2}})

y = ln (\frac{x ^{2}}{4})

\frac{d}{d x} (\frac{2 x ^{3} - 2}{3 x + 4})

x \to - 8 lim (\frac{x ^{2} - 3}{8 - x})

What is area 7cos(7x),7-7cos(7x),[0, pi/7 ] ?
The answer to area 7cos(7x),7-7cos(7x),[0, pi/7 ] is -(2pi)/3+pi+2sqrt(3)