What is the derivative of y=ln((x^2)/4) ?

The derivative of y=ln((x^2)/4) is 2/x

What is the first derivative of y=ln((x^2)/4) ?

The first derivative of y=ln((x^2)/4) is 2/x

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derivative of

y = ln (\frac{x ^{2}}{4})

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (\frac{x ^{2}}{4}))

Apply the chain rule:

\frac{1}{\frac{x ^{2}}{4}} \frac{d}{d x} (\frac{x ^{2}}{4})

= \frac{1}{\frac{x ^{2}}{4}} \frac{d}{d x} (\frac{x ^{2}}{4})

\frac{d}{d x} (\frac{x ^{2}}{4}) = \frac{x}{2}

= \frac{1}{\frac{x ^{2}}{4}} \cdot \frac{x}{2}

Simplify

\frac{1}{\frac{x ^{2}}{4}} \cdot \frac{x}{2} : \frac{2}{x}

= \frac{2}{x}

\frac{d}{d x} (\frac{2 x ^{3} - 2}{3 x + 4})

x \to - 8 lim (\frac{x ^{2} - 3}{8 - x})

f^{^{'}} (x) = (3 x^{5} - 2)^{20}

\int \frac{8}{1 - cos ( 2 x )} d x

\int \frac{sin ( 2 x )}{4} d x

What is the derivative of y=ln((x^2)/4) ?
The derivative of y=ln((x^2)/4) is 2/x
What is the first derivative of y=ln((x^2)/4) ?
The first derivative of y=ln((x^2)/4) is 2/x