What is the derivative of 2/(t^3) ?

The derivative of 2/(t^3) is -6/(t^4)

What is the first derivative of 2/(t^3) ?

The first derivative of 2/(t^3) is -6/(t^4)

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derivative of

\frac{2}{t ^{3}}

- \frac{6}{t ^{4}}

Solution steps

\frac{d}{d t} (\frac{2}{t ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (\frac{1}{t ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d t} (t^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 t^{- 3 - 1})

Simplify

2 (- 3 t^{- 3 - 1}) : - \frac{6}{t ^{4}}

= - \frac{6}{t ^{4}}

y^{^{'}} + 3 y = x e^{- 2 x}

\frac{\partial}{\partial y} (- sin (x) sin (y))

n = 0 \sum \infty \frac{( x ^{n} )}{n}

\frac{d y}{y ln ( \frac{k}{y} )} = c d x

What is the derivative of 2/(t^3) ?
The derivative of 2/(t^3) is -6/(t^4)
What is the first derivative of 2/(t^3) ?
The first derivative of 2/(t^3) is -6/(t^4)