What is inverse oflaplace (1960)/(s^2+196) ?

The answer to inverse oflaplace (1960)/(s^2+196) is 140sin(14t)

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inverse oflaplace (1960)/(s^2+196)

inverse laplace

\frac{1960}{s ^{2} + 196}

140 sin (14 t)

Solution steps

L^{- 1} {\frac{1960}{s ^{2} + 196}}

= L^{- 1} {140 \cdot \frac{14}{s ^{2} + 1 4 ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 140 L^{- 1} {\frac{14}{s ^{2} + 1 4 ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{14}{s ^{2} + 1 4 ^{2}}} = sin (14 t)

= 140 sin (14 t)

y^{^{'}} = - 3 y + 2 e^{- x}

(4, - 2), (- 8, - 1)

x \to 3 lim (25 - x^{2})

y = sin (tan (6 x))

\frac{\partial}{\partial y} (x y + ln (y) + 2 x^{2})

What is inverse oflaplace (1960)/(s^2+196) ?
The answer to inverse oflaplace (1960)/(s^2+196) is 140sin(14t)