What is inverse oflaplace (11)/((s-1)^3) ?

The answer to inverse oflaplace (11)/((s-1)^3) is (11e^tt^2)/2

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inverse oflaplace (11)/((s-1)^3)

inverse laplace

\frac{11}{( s - 1 ) ^{3}}

\frac{11 e ^{t} t ^{2}}{2}

Solution steps

L^{- 1} {\frac{11}{( s - 1 ) ^{3}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {F (s - a)} = e^{a t} f (t)

For

\frac{11}{( s - 1 ) ^{3}} : a = 1, F (s) = \frac{11}{s ^{3}}

= e^{t} L^{- 1} {\frac{11}{s ^{3}}}

L^{- 1} {\frac{11}{s ^{3}}} : \frac{11 t ^{2}}{2}

= \frac{11 e ^{t} t ^{2}}{2}

\int_{0}^{2} 8 x - \frac{1}{8} x d x

n = 0 \sum \infty 2 x^{2 n}

\int_{3}^{\infty} e^{- x} d x

x \to 3 + lim (\frac{3}{x ^{2} - 9})

\int_{0}^{0.9} \frac{1}{1 - x} d x

What is inverse oflaplace (11)/((s-1)^3) ?
The answer to inverse oflaplace (11)/((s-1)^3) is (11e^tt^2)/2