What is the limit as x approaches 3+of 3/(x^2-9) ?

The limit as x approaches 3+of 3/(x^2-9) is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3+of 3/(x^2-9)

x \to 3 + lim (\frac{3}{x ^{2} - 9})

\infty

Solution steps

x \to 3 + lim (\frac{3}{x ^{2} - 9})

For

x

approaching

3

from the right

, x > 3 \Rightarrow x^{2} - 9 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int_{0}^{0.9} \frac{1}{1 - x} d x

8 y^{^{''}} + 2 y^{^{'}} - y = 0

sin (x), cos (x), [0, \frac{π}{2}]

\frac{d y}{d x} = 2 x e^{4 y}

y^{^{''}} - 2 y^{^{'}} + y = - 6 - 3 x + \frac{2 e ^{x}}{x}

What is the limit as x approaches 3+of 3/(x^2-9) ?
The limit as x approaches 3+of 3/(x^2-9) is infinity