What is the derivative of 2^{(3x}) ?

The derivative of 2^{(3x}) is 3ln(2)*8^x

What is the first derivative of 2^{(3x}) ?

The first derivative of 2^{(3x}) is 3ln(2)*8^x

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\frac{d}{d x} (2^{(3 x)})

3 ln (2) \cdot 8^{x}

Solution steps

\frac{d}{d x} (2^{(3 x)})

Simplify

2^{(3 x)} : 8^{x}

= \frac{d}{d x} (8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 8^{x} ln (8)

Simplify

ln (8) : 3 ln (2)

= 3 ln (2) \cdot 8^{x}

\int r^{2} cos (θ) d r

\frac{d}{d x} (9 + 6 x)

\frac{d}{d x} (4 - 2 x^{2})

x^{2} e^{x} - 2 x e^{x} + 7 e^{x}

x \to - 1 lim (x^{2} + 3 x + 2)

What is the derivative of 2^{(3x}) ?
The derivative of 2^{(3x}) is 3ln(2)*8^x
What is the first derivative of 2^{(3x}) ?
The first derivative of 2^{(3x}) is 3ln(2)*8^x