What is the integral from 1/5 to 7 of 8xln(5x) ?

The integral from 1/5 to 7 of 8xln(5x) is 8(-306/25+49/2 ln(35))

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integral from 1/5 to 7 of 8xln(5x)

\int_{\frac{1}{5}}^{7} 8 x ln (5 x) d x

8 (- \frac{306}{25} + \frac{49}{2} ln (35))

Solution steps

\int_{\frac{1}{5}}^{7} 8 x ln (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{\frac{1}{5}}^{7} x ln (5 x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (5 x) - \int \frac{x}{2} d x]_{\frac{1}{5}}^{7}

= 8 [\frac{1}{2} x^{2} ln (5 x) - \int \frac{x}{2} d x]_{\frac{1}{5}}^{7}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 8 [\frac{1}{2} x^{2} ln (5 x) - \frac{x ^{2}}{4}]_{\frac{1}{5}}^{7}

Compute the boundaries:

- \frac{306}{25} + \frac{49}{2} ln (35)

= 8 (- \frac{306}{25} + \frac{49}{2} ln (35))

y^{^{'}} + \frac{2}{x} y = 4 x

\frac{d}{d x} (sin^{2} (\frac{x}{2}))

\frac{d}{d x} (ln (7 x^{2} + 5 y^{2}))

4 t^{\frac{- 1}{8}} + 5 ln (t) + ln (5)

n = 1 \sum \infty \frac{3}{5 ^{n}} + \frac{2}{n}

What is the integral from 1/5 to 7 of 8xln(5x) ?
The integral from 1/5 to 7 of 8xln(5x) is 8(-306/25+49/2 ln(35))