What is the sum from n=1 to infinity of (2n)/(5n-8) ?

The sum from n=1 to infinity of (2n)/(5n-8) is diverges

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sum from n=1 to infinity of (2n)/(5n-8)

n = 1 \sum \infty \frac{2 n}{5 n - 8}

diverges

Solution steps

n = 1 \sum \infty \frac{2 n}{5 n - 8}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 1 \sum \infty \frac{n}{5 n - 8}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

\int (3 x^{2} - 1)^{4} 3 x d x

\int (x^{3} + 5) d x

x^{2} - 6 (3) + 9

3 x^{2} + 2

\int \frac{x}{4 x ^{2} + 1} d x

What is the sum from n=1 to infinity of (2n)/(5n-8) ?
The sum from n=1 to infinity of (2n)/(5n-8) is diverges