What is the derivative of 8/(1-x) ?

The derivative of 8/(1-x) is 8/((1-x)^2)

What is the first derivative of 8/(1-x) ?

The first derivative of 8/(1-x) is 8/((1-x)^2)

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derivative of

\frac{8}{1 - x}

\frac{8}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{1 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} ((1 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

= - \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 8 (- \frac{1}{( 1 - x ) ^{2}} (- 1))

Simplify

8 (- \frac{1}{( 1 - x ) ^{2}} (- 1)) : \frac{8}{( 1 - x ) ^{2}}

= \frac{8}{( 1 - x ) ^{2}}

\frac{d}{d t} (4 t^{2} + 2 t + 5)

\frac{d}{d x} (e^{c o s (x)} + e^{s i n (y)})

\frac{d}{d x} (lo g_{3} (5 x - 1))

y = \frac{5}{x}, (4, \frac{5}{4})

t^{2} \cdot t^{3} + 2

What is the derivative of 8/(1-x) ?
The derivative of 8/(1-x) is 8/((1-x)^2)
What is the first derivative of 8/(1-x) ?
The first derivative of 8/(1-x) is 8/((1-x)^2)