What is the first derivative of e^x+4 ?

The first derivative of e^x+4 is e^x

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derivative of e^x+4

\frac{d}{d x} (e^{x} + 4)

e^{x}

Solution steps

\frac{d}{d x} (e^{x} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (4)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (4) = 0

= e^{x} + 0

Simplify

= e^{x}

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