What is the derivative of f(r)=sqrt(r)+\sqrt[7]{r} ?

The derivative of f(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

What is the first derivative of f(r)=sqrt(r)+\sqrt[7]{r} ?

The first derivative of f(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}

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derivative of

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d r} (r) = \frac{1}{2 r}

= \frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

\int (2 x e^{- 3 x}) d x

x \to 0 lim (\frac{3 tan ( x )}{x})

y^{^{'}} + 2 sin (2 x) y = 2 sin (2 x), y (\frac{π}{2}) = 3

\frac{d x}{d y} = x y

\frac{d}{d x} (- csc (x) - sin (x))

What is the derivative of f(r)=sqrt(r)+\sqrt[7]{r} ?
The derivative of f(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}
What is the first derivative of f(r)=sqrt(r)+\sqrt[7]{r} ?
The first derivative of f(r)=sqrt(r)+\sqrt[7]{r} is 1/(2sqrt(r))+1/(7r^{6/7)}