What is the solution for y^'+2sin(2x)y=2sin(2x),y(pi/2)=3 ?

The solution for y^'+2sin(2x)y=2sin(2x),y(pi/2)=3 is y=2e^{cos(2x)+1}+1

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y^'+2sin(2x)y=2sin(2x),y(pi/2)=3

y^{^{'}} + 2 sin (2 x) y = 2 sin (2 x), y (\frac{π}{2}) = 3

y = 2 e^{c o s (2 x) + 1} + 1

Solution steps

y^{'} (x) + 2 sin (2 x) y = 2 sin (2 x)

Solve separable ODE:

y = 2 e^{c o s (2 x) + 1} + 1

y = 2 e^{c o s (2 x) + 1} + 1

\frac{d x}{d y} = x y

\frac{d}{d x} (- csc (x) - sin (x))

\int 5 sin^{3} (9 x) d x

\frac{\partial}{\partial y} (4 x y - 2 e^{2 x + y})

h \to 0 lim ((- 4)^{2} + 2 (- 4))

What is the solution for y^'+2sin(2x)y=2sin(2x),y(pi/2)=3 ?
The solution for y^'+2sin(2x)y=2sin(2x),y(pi/2)=3 is y=2e^{cos(2x)+1}+1