What is (\partial)/(\partial y)(4xy-2e^{2x+y}) ?

The answer to (\partial)/(\partial y)(4xy-2e^{2x+y}) is 4x-2e^{2x+y}

Popular >

(\partial)/(\partial y)(4xy-2e^{2x+y})

\frac{\partial}{\partial y} (4 x y - 2 e^{2 x + y})

4 x - 2 e^{2 x + y}

Solution steps

\frac{\partial}{\partial y} (4 x y - 2 e^{2 x + y})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x y) - \frac{\partial}{\partial y} (2 e^{2 x + y})

\frac{\partial}{\partial y} (4 x y) = 4 x

\frac{\partial}{\partial y} (2 e^{2 x + y}) = 2 e^{2 x + y}

= 4 x - 2 e^{2 x + y}

h \to 0 lim ((- 4)^{2} + 2 (- 4))

\int \frac{x ^{2}}{21 + 4 x - x ^{2}} d x

\frac{( s + 9 )}{( s ^{2} + 6 s + 34 )}

\int x^{2} x^{3} + 19 d x

\frac{d y}{d x} - \frac{2}{x} y = \frac{3}{x ^{2}} y^{4}

What is (\partial)/(\partial y)(4xy-2e^{2x+y}) ?
The answer to (\partial)/(\partial y)(4xy-2e^{2x+y}) is 4x-2e^{2x+y}