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Popular >

derivative of h(t)=3ln(t^6)

Solution

derivative of

h (t) = 3 ln (t^{6})

Solution

\frac{18}{t}

Solution steps

\frac{d}{d t} (3 ln (t^{6}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (ln (t^{6}))

Apply the chain rule:

\frac{1}{t ^{6}} \frac{d}{d t} (t^{6})

= \frac{1}{t ^{6}} \frac{d}{d t} (t^{6})

\frac{d}{d t} (t^{6}) = 6 t^{5}

= 3 \cdot \frac{1}{t ^{6}} \cdot 6 t^{5}

Simplify

3 \cdot \frac{1}{t ^{6}} \cdot 6 t^{5} : \frac{18}{t}

= \frac{18}{t}

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\int 24 + cos (x) d x

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\frac{- 4 x}{x ^{2} + 1} (- 1.2)

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\frac{d}{d x} (x^{2} + x z - y + y^{2} + y z + 3 z^{2})

integral of x*e^{x/4}

\int x \cdot e^{\frac{x}{4}} d x

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\frac{\partial}{\partial x} (4 \frac{y}{x})

Frequently Asked Questions (FAQ)

What is the derivative of h(t)=3ln(t^6) ?
The derivative of h(t)=3ln(t^6) is (18)/t
What is the first derivative of h(t)=3ln(t^6) ?
The first derivative of h(t)=3ln(t^6) is (18)/t