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Popular >

area 6-x^2,x^2-2,[0,3]

Solution

area

6 - x^{2}, x^{2} - 2, [0, 3]

Solution

\frac{46}{3}

+1

Solution steps

Apply the area formula:

\int_{0}^{3} 6 - x^{2} - (x^{2} - 2) d x

Solve

\int_{0}^{3} 6 - x^{2} - (x^{2} - 2) d x : \frac{46}{3}

The area is:

= \frac{46}{3}

Popular Examples

integral of (ln(y))/(ln(y))

\int \frac{ln ( y )}{ln ( y )} d y

e^{t^2}y^'+(t+ty^2)=0,y(0)=1

e^{t^{2}} y^{^{'}} + (t + t y^{2}) = 0, y (0) = 1

tangent of (64x)/(x^2+64)tangent of

\frac{64 x}{x ^{2} + 64}

(\partial)/(\partial y)(2x^3-x^2y)

\frac{\partial}{\partial y} (2 x^{3} - x^{2} y)

integral of (t^2-1)(4+3t)

\int (t^{2} - 1) (4 + 3 t) d t

Frequently Asked Questions (FAQ)

What is area 6-x^2,x^2-2,[0,3] ?
The answer to area 6-x^2,x^2-2,[0,3] is 46/3