What is (\partial)/(\partial y)(2x^3-x^2y) ?

The answer to (\partial)/(\partial y)(2x^3-x^2y) is -x^2

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(\partial)/(\partial y)(2x^3-x^2y)

\frac{\partial}{\partial y} (2 x^{3} - x^{2} y)

- x^{2}

Solution steps

\frac{\partial}{\partial y} (2 x^{3} - x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{3}) - \frac{\partial}{\partial y} (x^{2} y)

\frac{\partial}{\partial y} (2 x^{3}) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

= 0 - x^{2}

Simplify

= - x^{2}

\int (t^{2} - 1) (4 + 3 t) d t

f (x) = x^{4}, at x = 1

y = \frac{6}{x}, (25, \frac{6}{5})

\frac{x ^{2}}{7 + x}

x \to \infty lim (\frac{( 2 x ^{2} + 1 )}{3 x - 5})

What is (\partial)/(\partial y)(2x^3-x^2y) ?
The answer to (\partial)/(\partial y)(2x^3-x^2y) is -x^2