What is the tangent of f(x)=x^4,\at x=1 ?

The tangent of f(x)=x^4,\at x=1 is y=4x-3

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tangent of f(x)=x^4,\at x=1

tangent of

f (x) = x^{4}, at x = 1

y = 4 x - 3

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

x = 1 : m = 4

Find the line with slope m=

4

and passing through

(1, 1) : y = 4 x - 3

y = 4 x - 3

y = \frac{6}{x}, (25, \frac{6}{5})

\frac{x ^{2}}{7 + x}

x \to \infty lim (\frac{( 2 x ^{2} + 1 )}{3 x - 5})

y^{^{''}} - 2 y^{^{'}} = 2 t

x \to 3 + lim (\frac{x ^{2} + x}{x - 3})

What is the tangent of f(x)=x^4,\at x=1 ?
The tangent of f(x)=x^4,\at x=1 is y=4x-3