What is the solution for y^{'''}-5y^{''}+6y^'=0 ?

The solution for y^{'''}-5y^{''}+6y^'=0 is y=c_{1}+c_{2}e^{2t}+c_{3}e^{3t}

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y^{'''}-5y^{''}+6y^'=0

y^{^{'''}} - 5 y^{^{''}} + 6 y^{^{'}} = 0

y = c_{1} + c_{2} e^{2 t} + c_{3} e^{3 t}

Solution steps

y^{'''} (t) - 5 y^{''} (t) + 6 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{2 t} + c_{3} e^{3 t}

y = c_{1} + c_{2} e^{2 t} + c_{3} e^{3 t}

x \to 3 - lim (- \frac{2}{3 - x})

\frac{\partial}{\partial x} (3 x e^{2 x y})

\int \frac{( 8 x ^{2} + 3 x + 8 )}{( x ^{2} + 1 ) ^{2}} d x

y^{^{'}} = x e^{x}

\int_{0}^{l n (4)} π (e^{- x})^{2} d x

What is the solution for y^{'''}-5y^{''}+6y^'=0 ?
The solution for y^{'''}-5y^{''}+6y^'=0 is y=c_{1}+c_{2}e^{2t}+c_{3}e^{3t}