What is the slope of y= 1/(sqrt(x)),\at ,x=4 ?

The slope of y= 1/(sqrt(x)),\at ,x=4 is -1/16

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slope of y= 1/(sqrt(x)),\at ,x=4

slope

y = \frac{1}{x}, at, x = 4

- \frac{1}{16}

Solution steps

y = \frac{1}{x}

In order to find the slope of the function, take the derivative of

\frac{1}{x}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{2 x ^{\frac{3}{2}}}

- \frac{1}{2 x ^{\frac{3}{2}}}

Find the value of

- \frac{1}{2 x ^{\frac{3}{2}}}

for

x = 4 : - \frac{1}{16}

- \frac{1}{16}

\frac{d}{d x} (a cos (t))

\int \frac{e ^{x} ( x - 1 )}{x ^{2}} d x

\int \frac{1}{3 cos ( x ) - 4 sin ( x )} d x

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{x})

x \to - 3 - lim (\frac{∣ x + 3 ∣}{x + 3})

What is the slope of y= 1/(sqrt(x)),\at ,x=4 ?
The slope of y= 1/(sqrt(x)),\at ,x=4 is -1/16