What is the derivative of f(x)=x^4-2x^3-12x^2+4x-3 ?

The derivative of f(x)=x^4-2x^3-12x^2+4x-3 is 4x^3-6x^2-24x+4

What is the first derivative of f(x)=x^4-2x^3-12x^2+4x-3 ?

The first derivative of f(x)=x^4-2x^3-12x^2+4x-3 is 4x^3-6x^2-24x+4

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derivative of

f (x) = x^{4} - 2 x^{3} - 12 x^{2} + 4 x - 3

4 x^{3} - 6 x^{2} - 24 x + 4

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{3} - 12 x^{2} + 4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (12 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (12 x^{2}) = 24 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 4 x^{3} - 6 x^{2} - 24 x + 4 - 0

Simplify

= 4 x^{3} - 6 x^{2} - 24 x + 4

\int 4 sin^{3} (x co) s^{7} x d x

\frac{d}{d x} (x^{2} 5 - 2 x)

\frac{\partial}{\partial v} (cos (v))

\int \frac{1}{2} e^{x} d x

y^{^{'}} - \frac{y}{3} = 0

What is the derivative of f(x)=x^4-2x^3-12x^2+4x-3 ?
The derivative of f(x)=x^4-2x^3-12x^2+4x-3 is 4x^3-6x^2-24x+4
What is the first derivative of f(x)=x^4-2x^3-12x^2+4x-3 ?
The first derivative of f(x)=x^4-2x^3-12x^2+4x-3 is 4x^3-6x^2-24x+4