What is the derivative of (2x-1)/(x+2) ?

The derivative of (2x-1)/(x+2) is 5/((x+2)^2)

What is the first derivative of (2x-1)/(x+2) ?

The first derivative of (2x-1)/(x+2) is 5/((x+2)^2)

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derivative of

\frac{2 x - 1}{x + 2}

\frac{5}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 1}{x + 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) ( x + 2 ) - \frac{d}{d x} ( x + 2 ) ( 2 x - 1 )}{( x + 2 ) ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (x + 2) = 1

= \frac{2 ( x + 2 ) - 1 \cdot ( 2 x - 1 )}{( x + 2 ) ^{2}}

Simplify

\frac{2 ( x + 2 ) - 1 \cdot ( 2 x - 1 )}{( x + 2 ) ^{2}} : \frac{5}{( x + 2 ) ^{2}}

= \frac{5}{( x + 2 ) ^{2}}

ln (sin^{2} (x))

\frac{d y}{d x} = x + 2 x y

\frac{d}{d x} ((3 x + 1)^{3})

n = 2 \sum \infty \frac{1}{2 n \cdot ln ( n )}

x^{- 2} (5 x^{2} - 4)^{3}

What is the derivative of (2x-1)/(x+2) ?
The derivative of (2x-1)/(x+2) is 5/((x+2)^2)
What is the first derivative of (2x-1)/(x+2) ?
The first derivative of (2x-1)/(x+2) is 5/((x+2)^2)