What is the derivative of (3x+1^3) ?

The derivative of (3x+1^3) is 9(3x+1)^2

What is the first derivative of (3x+1^3) ?

The first derivative of (3x+1^3) is 9(3x+1)^2

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\frac{d}{d x} ((3 x + 1)^{3})

9 (3 x + 1)^{2}

Solution steps

\frac{d}{d x} ((3 x + 1)^{3})

Apply the chain rule:

3 (3 x + 1)^{2} \frac{d}{d x} (3 x + 1)

= 3 (3 x + 1)^{2} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 3 (3 x + 1)^{2} \cdot 3

Simplify

= 9 (3 x + 1)^{2}

n = 2 \sum \infty \frac{1}{2 n \cdot ln ( n )}

x^{- 2} (5 x^{2} - 4)^{3}

(2 x^{3} + x y^{2}) + (x^{2} y + 2 y^{3}) \frac{d y}{d x} = 0

\int_{0}^{t} e^{- s^{2}} d s

x \to - 5 lim (\frac{x ^{2} - 2}{5 - x})

What is the derivative of (3x+1^3) ?
The derivative of (3x+1^3) is 9(3x+1)^2
What is the first derivative of (3x+1^3) ?
The first derivative of (3x+1^3) is 9(3x+1)^2