What is the integral from 0 to t of e^{-s^2} ?

The integral from 0 to t of e^{-s^2} is (sqrt(pi))/2 \erf(t)

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integral from 0 to t of e^{-s^2}

\int_{0}^{t} e^{- s^{2}} d s

\frac{π}{2} erf (t)

Solution steps

\int_{0}^{t} e^{- s^{2}} d s

Use the nonelementary integral:

\int e^{- s^{2}} d s = \frac{π}{2} erf (s)

= [\frac{π}{2} erf (s)]_{0}^{t}

Compute the boundaries:

\frac{π}{2} erf (t)

= \frac{π}{2} erf (t)

x \to - 5 lim (\frac{x ^{2} - 2}{5 - x})

\int \frac{x ^{3}}{3} \cdot \frac{1}{x} d x

\int \frac{- ln ( x )}{x ^{2}} d x

3 + y^{2}

y^{^{''}} - 2 y^{^{'}} = (4 t + 9) sin (2 t)

What is the integral from 0 to t of e^{-s^2} ?
The integral from 0 to t of e^{-s^2} is (sqrt(pi))/2 \erf(t)