What is the derivative of sqrt(3+y^2) ?

The derivative of sqrt(3+y^2) is y/(sqrt(3+y^2))

What is the first derivative of sqrt(3+y^2) ?

The first derivative of sqrt(3+y^2) is y/(sqrt(3+y^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

3 + y^{2}

\frac{y}{3 + y ^{2}}

Solution steps

\frac{d}{d y} (3 + y^{2})

Apply the chain rule:

\frac{1}{2 3 + y ^{2}} \frac{d}{d y} (3 + y^{2})

= \frac{1}{2 3 + y ^{2}} \frac{d}{d y} (3 + y^{2})

\frac{d}{d y} (3 + y^{2}) = 2 y

= \frac{1}{2 3 + y ^{2}} \cdot 2 y

Simplify

\frac{1}{2 3 + y ^{2}} \cdot 2 y : \frac{y}{3 + y ^{2}}

= \frac{y}{3 + y ^{2}}

y^{^{''}} - 2 y^{^{'}} = (4 t + 9) sin (2 t)

\int 2 sec^{2} (x) d x

\int_{- 1}^{0} \frac{1}{x} d x

\frac{d}{d x} (\frac{3}{2} sin (2 x))

\int (x^{2} - y) d x

What is the derivative of sqrt(3+y^2) ?
The derivative of sqrt(3+y^2) is y/(sqrt(3+y^2))
What is the first derivative of sqrt(3+y^2) ?
The first derivative of sqrt(3+y^2) is y/(sqrt(3+y^2))