What is the derivative of y=-x^2+4x ?

The derivative of y=-x^2+4x is -2x+4

What is the first derivative of y=-x^2+4x ?

The first derivative of y=-x^2+4x is -2x+4

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derivative of

y = - x^{2} + 4 x

- 2 x + 4

Solution steps

\frac{d}{d x} (- x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= - 2 x + 4

y^{^{''}} + 2 y^{^{'}} + y = sin (x)

\int \frac{x ^{4} + 2 x ^{2} - 1}{x} d x

\frac{d}{d x} (\frac{sin ( x ) + cos ( x )}{x ^{3} + x - 2})

n = 21 \sum \infty e^{- 0.06 n}

(x^{2} - 9) \frac{d y}{d x} + x y = 0

What is the derivative of y=-x^2+4x ?
The derivative of y=-x^2+4x is -2x+4
What is the first derivative of y=-x^2+4x ?
The first derivative of y=-x^2+4x is -2x+4