What is the solution for (x^2-9)(dy)/(dx)+xy=0 ?

The solution for (x^2-9)(dy)/(dx)+xy=0 is y=(c_{1})/(sqrt(x^2-9))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2-9)(dy)/(dx)+xy=0

(x^{2} - 9) \frac{d y}{d x} + x y = 0

y = \frac{c _{1}}{x ^{2} - 9}

Solution steps

(x^{2} - 9) \frac{d y}{d x} + x y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9}

y = \frac{c _{1}}{x ^{2} - 9}

\int 16 - 4 x^{2} d x

\frac{1}{2} sec (2 x)

\frac{d y}{d x} - \frac{y}{x} = 2 x^{2} ln (x)

x \to 1 lim (4 x^{2} - 2 x + 5)

\frac{d}{d x} (\frac{1 + \frac{1}{x}}{1 - \frac{1}{x}})

What is the solution for (x^2-9)(dy)/(dx)+xy=0 ?
The solution for (x^2-9)(dy)/(dx)+xy=0 is y=(c_{1})/(sqrt(x^2-9))