What is the derivative of 1/2 sec(2x) ?

The derivative of 1/2 sec(2x) is sec(2x)tan(2x)

What is the first derivative of 1/2 sec(2x) ?

The first derivative of 1/2 sec(2x) is sec(2x)tan(2x)

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derivative of

\frac{1}{2} sec (2 x)

sec (2 x) tan (2 x)

Solution steps

\frac{d}{d x} (\frac{1}{2} sec (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{2} sec (2 x) tan (2 x) \cdot 2

Simplify

\frac{1}{2} sec (2 x) tan (2 x) \cdot 2 : sec (2 x) tan (2 x)

= sec (2 x) tan (2 x)

\frac{d y}{d x} - \frac{y}{x} = 2 x^{2} ln (x)

x \to 1 lim (4 x^{2} - 2 x + 5)

\frac{d}{d x} (\frac{1 + \frac{1}{x}}{1 - \frac{1}{x}})

\frac{d y}{d x} = e^{3 x} \cdot e^{2 y}

x \to 3 lim (\frac{x ^{2} + 3}{x - 1})

What is the derivative of 1/2 sec(2x) ?
The derivative of 1/2 sec(2x) is sec(2x)tan(2x)
What is the first derivative of 1/2 sec(2x) ?
The first derivative of 1/2 sec(2x) is sec(2x)tan(2x)