What is the integral of x^2sqrt(x^3+31) ?

The integral of x^2sqrt(x^3+31) is 2/9 (x^3+31)^{3/2}+C

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integral of x^2sqrt(x^3+31)

\int x^{2} x^{3} + 31 d x

\frac{2}{9} (x^{3} + 31)^{\frac{3}{2}} + C

Solution steps

\int x^{2} x^{3} + 31 d x

Apply u-substitution

: \int \frac{u}{3} d u

= \int \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{3} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x^{3} + 31

= \frac{1}{3} \cdot \frac{2}{3} (x^{3} + 31)^{\frac{3}{2}}

Simplify

\frac{1}{3} \cdot \frac{2}{3} (x^{3} + 31)^{\frac{3}{2}} : \frac{2}{9} (x^{3} + 31)^{\frac{3}{2}}

= \frac{2}{9} (x^{3} + 31)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{9} (x^{3} + 31)^{\frac{3}{2}} + C

y = \frac{3}{x}, y = \frac{x}{12}, 1 \leq x \leq 6

x \to 0 lim (- 1 + \frac{1}{x})

\int_{2}^{3} \frac{16}{3 - x} d x

\frac{1}{2 x - 5}

\int 1 + cot^{2} (x) d x

What is the integral of x^2sqrt(x^3+31) ?
The integral of x^2sqrt(x^3+31) is 2/9 (x^3+31)^{3/2}+C