What is area y= 3/x ,y= x/(12),1<= x<= 6 ?

The answer to area y= 3/x ,y= x/(12),1<= x<= 6 is 3ln(6)-35/24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y= 3/x ,y= x/(12),1<= x<= 6

area

y = \frac{3}{x}, y = \frac{x}{12}, 1 \leq x \leq 6

3 ln (6) - \frac{35}{24}

Solution steps

Apply the area formula:

\int_{1}^{6} \frac{3}{x} - \frac{x}{12} d x

Solve

\int_{1}^{6} \frac{3}{x} - \frac{x}{12} d x : 3 ln (6) - \frac{35}{24}

The area is:

= 3 ln (6) - \frac{35}{24}

x \to 0 lim (- 1 + \frac{1}{x})

\int_{2}^{3} \frac{16}{3 - x} d x

\frac{1}{2 x - 5}

\int 1 + cot^{2} (x) d x

\frac{d}{d x} (\frac{x ^{3}}{6} - 3 x)

What is area y= 3/x ,y= x/(12),1<= x<= 6 ?
The answer to area y= 3/x ,y= x/(12),1<= x<= 6 is 3ln(6)-35/24