What is the solution for (dy)/(dx)=1-y^2 ?

The solution for (dy)/(dx)=1-y^2 is y=-(e^{2x+2c_{1}})/(1-e^{2(x+c_{1))}}-1/(1-e^{2(x+c_{1))}}

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(dy)/(dx)=1-y^2

\frac{d y}{d x} = 1 - y^{2}

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

Solution steps

\frac{d y}{d x} = 1 - y^{2}

Solve separable ODE:

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

y = - \frac{e ^{2 x + 2 c_{1}}}{1 - e ^{2 (x + c_{1})}} - \frac{1}{1 - e ^{2 (x + c_{1})}}

\int e^{x} - \frac{1}{x} + 4 + 5 x^{3} d x

\int \frac{v ^{2}}{- v ^{2} + 3} d v

\int sin (3 x + 4) d x

\frac{d}{d x} (\frac{2}{( x - 3 t ) ^{2} + 1})

x \to 1 lim (x (x - 2))

What is the solution for (dy)/(dx)=1-y^2 ?
The solution for (dy)/(dx)=1-y^2 is y=-(e^{2x+2c_{1}})/(1-e^{2(x+c_{1))}}-1/(1-e^{2(x+c_{1))}}