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Popular >

integral of sin(3x+4)

Solution

\int sin (3 x + 4) d x

Solution

- \frac{1}{3} cos (3 x + 4) + C

Solution steps

\int sin (3 x + 4) d x

Apply u-substitution

: \int sin (u) \frac{1}{3} d u

= \int sin (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{3} (- cos (u))

Substitute back

u = 3 x + 4

= \frac{1}{3} (- cos (3 x + 4))

Simplify

= - \frac{1}{3} cos (3 x + 4)

Add a constant to the solution

= - \frac{1}{3} cos (3 x + 4) + C

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x \to 1 lim (x (x - 2))

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x \to 0 + lim (x)

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n = 0 \sum \infty sin (\frac{nπ}{7})

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Frequently Asked Questions (FAQ)

What is the integral of sin(3x+4) ?
The integral of sin(3x+4) is -1/3 cos(3x+4)+C