What is the derivative of 2-x^{2/3} ?

The derivative of 2-x^{2/3} is -2/(3x^{1/3)}

What is the first derivative of 2-x^{2/3} ?

The first derivative of 2-x^{2/3} is -2/(3x^{1/3)}

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\frac{d}{d x} (2 - x^{\frac{2}{3}})

- \frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (2 - x^{\frac{2}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d}{d x} (x^{\frac{2}{3}})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

= 0 - \frac{2}{3 x ^{\frac{1}{3}}}

Simplify

= - \frac{2}{3 x ^{\frac{1}{3}}}

\int \frac{x ^{4} + 1}{2 x ^{2}} d x

\int \frac{x}{x ^{4} + 2} d x

f (x) = \frac{5}{x}, at x = 1

\int t e^{t} d t

\int \frac{x}{x ^{4} + 1} d x

What is the derivative of 2-x^{2/3} ?
The derivative of 2-x^{2/3} is -2/(3x^{1/3)}
What is the first derivative of 2-x^{2/3} ?
The first derivative of 2-x^{2/3} is -2/(3x^{1/3)}