What is area y=x,y=0.2x^2-1.2x+3 ?

The answer to area y=x,y=0.2x^2-1.2x+3 is 15.88084…

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area y=x,y=0.2x^2-1.2x+3

area

y = x, y = 0.2 x^{2} - 1.2 x + 3

15.88084 \dots

Solution steps

Apply the area formula:

\int_{\frac{11 - 61}{2}}^{\frac{11 + 61}{2}} x - (0.2 x^{2} - 1.2 x + 3) d x

Solve

\int_{\frac{11 - 61}{2}}^{\frac{11 + 61}{2}} x - (0.2 x^{2} - 1.2 x + 3) d x : 15.88084 \dots

The area is:

= 15.88084 \dots

25 + 16 t^{2}

(x + y)^{2}

x 2 - x^{2}

e^{- 3 t} sin (4 t)

\int \frac{1}{y ( y ^{2} + 1 )} d y

What is area y=x,y=0.2x^2-1.2x+3 ?
The answer to area y=x,y=0.2x^2-1.2x+3 is 15.88084…