What is the limit as x approaches-1 of x/(x^2-1) ?

The limit as x approaches-1 of x/(x^2-1) is diverges

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limit as x approaches-1 of x/(x^2-1)

x \to - 1 lim (\frac{x}{x ^{2} - 1})

diverges

Solution steps

x \to - 1 lim (\frac{x}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x}{x ^{2} - 1}) = \infty

x \to - 1 - lim (\frac{x}{x ^{2} - 1}) = - \infty

= diverges

\frac{x ^{3} + 3 x}{x ^{2} - 4 x + 3}

x \to 4 - lim (\frac{∣ x - 4 ∣}{x - 4})

\int (x^{3} + x) x^{4} + 2 x^{2} d x

\frac{\partial}{\partial x} (sin (x z^{2}) - x y^{2})

\int x a e^{- a x} d x

What is the limit as x approaches-1 of x/(x^2-1) ?
The limit as x approaches-1 of x/(x^2-1) is diverges