What is the derivative of 1+x^3 ?

The derivative of 1+x^3 is 3x^2

What is the first derivative of 1+x^3 ?

The first derivative of 1+x^3 is 3x^2

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\frac{d}{d x} (1 + x^{3})

3 x^{2}

Solution steps

\frac{d}{d x} (1 + x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{3})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 0 + 3 x^{2}

Simplify

= 3 x^{2}

f (x) = 5 x + 6, at x = 2

x \frac{d y}{d x} + 2 y = 8 x^{2}

n = 0 \sum \infty \frac{5}{4 ^{n}}

\int ln (6 x + 7) d x

(1 + cos (t)) y^{^{'}} = (1 - e^{- y}) sin (t)