What is (\partial)/(\partial x)(e^x+cos(y)) ?

The answer to (\partial)/(\partial x)(e^x+cos(y)) is e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(e^x+cos(y))

\frac{\partial}{\partial x} (e^{x} + cos (y))

e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{x} + cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (cos (y))

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (cos (y)) = 0

= e^{x} + 0

Simplify

= e^{x}

f (x) = \frac{3 x - 7}{5 x - 2}

\frac{d}{d x} (\frac{2}{3} x^{2} - 5 x + \frac{3}{x} + 7)

y = 20 - x, y = x, y = 1

y^{^{'}} = - a y (1 + 3 y)

\frac{\partial}{\partial y} (100 e^{- 2 x^{2} - y^{2}})

What is (\partial)/(\partial x)(e^x+cos(y)) ?
The answer to (\partial)/(\partial x)(e^x+cos(y)) is e^x