What is the solution for y^'=-ay(1+3y) ?

The solution for y^'=-ay(1+3y) is y=(e^{c_{1}})/(e^{at)-3e^{c_{1}}}

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y^'=-ay(1+3y)

y^{^{'}} = - a y (1 + 3 y)

y = \frac{e ^{c_{1}}}{e ^{a t} - 3 e ^{c_{1}}}

Solution steps

y^{'} (t) = - a y (t) (1 + 3 y)

Solve separable ODE:

y = \frac{e ^{c_{1}}}{e ^{a t} - 3 e ^{c_{1}}}

y = \frac{e ^{c_{1}}}{e ^{a t} - 3 e ^{c_{1}}}

\frac{\partial}{\partial y} (100 e^{- 2 x^{2} - y^{2}})

\int \frac{5 sin ^{3} ( x )}{cos ( x )} d x

\frac{\partial}{\partial x} (x^{3} y)

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y^{^{''}} + 19 y = 0

What is the solution for y^'=-ay(1+3y) ?
The solution for y^'=-ay(1+3y) is y=(e^{c_{1}})/(e^{at)-3e^{c_{1}}}