What is the sum from n=0 to infinity of (3/2)^n ?

The sum from n=0 to infinity of (3/2)^n is diverges

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sum from n=0 to infinity of (3/2)^n

n = 0 \sum \infty (\frac{3}{2})^{n}

diverges

Solution steps

n = 0 \sum \infty (\frac{3}{2})^{n}

Apply Series Geometric Test:

diverges

= diverges

\frac{d}{d x} (\frac{4 x + a 1 + x}{x ^{2} - 1})

d x + e^{2 x} d y = 0

\frac{A}{y ^{14}} + B e^{y}

x \to 2 - lim (- 3)

\frac{d}{d x} (x sin (tan (x)))

What is the sum from n=0 to infinity of (3/2)^n ?
The sum from n=0 to infinity of (3/2)^n is diverges