What is the tangent of 10-2e^x ?

The tangent of 10-2e^x is y=-2e^{a_{0}}x+10-2e^{a_{0}}+2a_{0}e^{a_{0}}

Popular >

tangent of 10-2e^x

tangent of

10 - 2 e^{x}

y = - 2 e^{a_{0}} x + 10 - 2 e^{a_{0}} + 2 a_{0} e^{a_{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 10 - 2 e^{a_{0}})

Find the slope of

y = 10 - 2 e^{x} : \frac{d y}{d x} = - 2 e^{x}

Compute the slope of

y = 10 - 2 e^{x}

x = a_{0} : m = - 2 e^{a_{0}}

Find the line with slope m=

- 2 e^{a_{0}}

and passing through

(a_{0}, 10 - 2 e^{a_{0}}) : y = - 2 e^{a_{0}} x + 10 - 2 e^{a_{0}} + 2 a_{0} e^{a_{0}}

y = - 2 e^{a_{0}} x + 10 - 2 e^{a_{0}} + 2 a_{0} e^{a_{0}}

\frac{d}{d x} (sin (4 x - 5))

(\frac{x}{sin ( y )} + 2) d x + \frac{( x ^{2} + 1 ) cos ( y )}{cos ( 2 y ) - 1} d y = 0

\int e^{6 x + e^{6 x}} d x

(- 4.4) (- 6.6)

\int (x + 4)^{3} d x

What is the tangent of 10-2e^x ?
The tangent of 10-2e^x is y=-2e^{a_{0}}x+10-2e^{a_{0}}+2a_{0}e^{a_{0}}