What is the derivative of e^{x^4+9x} ?

The derivative of e^{x^4+9x} is e^{x^4+9x}(4x^3+9)

What is the first derivative of e^{x^4+9x} ?

The first derivative of e^{x^4+9x} is e^{x^4+9x}(4x^3+9)

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derivative of

e^{x^{4} + 9 x}

e^{x^{4} + 9 x} (4 x^{3} + 9)

Solution steps

\frac{d}{d x} (e^{x^{4} + 9 x})

Apply the chain rule:

e^{x^{4} + 9 x} \frac{d}{d x} (x^{4} + 9 x)

= e^{x^{4} + 9 x} \frac{d}{d x} (x^{4} + 9 x)

\frac{d}{d x} (x^{4} + 9 x) = 4 x^{3} + 9

= e^{x^{4} + 9 x} (4 x^{3} + 9)

\frac{d y}{d x}, 5 cos (x y) = 6 x + 7 y

\int sin (2 x) + cos (2 x) d x

x = y - y^{2}, x = y^{2} - 3

y^{^{''}} - 4 y^{^{'}} - 45 y = 0

\int cos^{4} (3 t) d t

What is the derivative of e^{x^4+9x} ?
The derivative of e^{x^4+9x} is e^{x^4+9x}(4x^3+9)
What is the first derivative of e^{x^4+9x} ?
The first derivative of e^{x^4+9x} is e^{x^4+9x}(4x^3+9)